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3.2x^2+2x-2=0
a = 3.2; b = 2; c = -2;
Δ = b2-4ac
Δ = 22-4·3.2·(-2)
Δ = 29.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{29.6}}{2*3.2}=\frac{-2-\sqrt{29.6}}{6.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{29.6}}{2*3.2}=\frac{-2+\sqrt{29.6}}{6.4} $
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